Question

A solution is prepared by dissolving 38.7g of nonelectrolyte into 218g of water. The freezing point of the solution is measured to be -5.53°C. Calculate the molar mass of the solute. kf of water = 1.86°C/m

Answer 1

Moles of water $=\frac{218}{18}=12.11moles$

Moles of solute = 12.11

Molar mass$=\frac{38.7}{12.11}=3.19g/mol$