Answer to Question #263816 in General Chemistry for Jhase

Question

2Al + MnO ---> Al2O3 + 3Mn

Determine the limiting reactant and mass of the remaining excess reagent of each of the given initial concentrations of reactants. Then explain further the reason a compound was considered the limiting reactants.

a.) 2 moles Al and 2 moles MnO

b.) 100g Al and 200g MnO

c.) 1.8 mol Al and 1.4 mol MnO

Answer 1

Moles ratio of Al:Al203

= 2:1

2/2= 1

MnO:Al2O3= 1:1

2moles

1+2= 3moles of Al2O3