Hydrogen gas can be collected from the reaction of a metal element with a strong acid as
shown. When a 500.0 mg iron metal sample was soaked in 50.00 mL 0.500 M HNO3, 16.00 mg H2 was collected. How efficient is this process?
2Fe + 6HNO3 → 2Fe(NO3)3 + 3H2
From the question, we have 500mg of iron which is (500/1000)g which is 0.5g
And for HNO3 we have to get the mass
So we first get the no of moles which is;
n=CV
n=0.5×0.05
n=0.025
Mass=mole×molar mass
Mass=0.025×63
Mass=1.575g
So now we'll find the limiting reagent
If 112g of Iron react with 378g of HNO3
0.5g- - - - - - - - - - - - - - - Xg of HNO3
X=(378×0.5)/112
X=1.69g
Therefore HNO3 is the limiting reagent
If 378g of HNO3 produces 6g of H2
1.575g - - - - - - - - - - - - - - Xg of
X=0.025g
Efficiency =(actual yield/theory yield)×100
=(0.016/0.025)×100
Efficiency=64%
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