What is the change in internal energy of a system if the surroundings absorb 145 J of heat from the system while doing 98 J of work on the system?
This is the first law of thermodynamics
ΔU=A+Q=A−Q=98−145=−47\Delta U=A+Q=A-Q=98-145=-47ΔU=A+Q=A−Q=98−145=−47 J
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