Answer to Question #263779 in General Chemistry for Marry

Question

Phosphoric acid (H3,PO4) is a key ingredient in soft drinks that gives it a

sharper flavor. One way to produce this acid is with the aid of mineral

fluoroapatite (Ca5(PO4)3F) following this reaction:

Ca5(PO4)3F + 5H2SO4 → 3H3PO4 + 5CaSO4 + HF

If 24.5 g Ca5(PO4)3F is mixed with 89.7 g H2SO4

, how much H3PO4 will form?

Answer 1

$Ca_5(PO_4)_3F + 5H_2SO_4 → 3H_3PO_4 + 5CaSO_4 + HF$

number of moles of fluoroapatite = 24.5g/138.05g = 0.177 mol

number of moles of sulphuric acid = 89.7g/98g = 0.915 mol

number of reacting moles = 0.915/5 = 0.183 mol

the limiting reactant is fluoroapatite.

$\therefore$ 0.183 moles of phosphoric acid is formed.

mass of the phosphoric acid = number of moles formed × number of stoichiometric moles × mass of phosphoric acid = 0.183 × 5 × 98 = 89.67g$.$