Answer to Question #258745 in General Chemistry for Madelyn

Question

If there is a mass percentage of 24.5% gold in an ore vein. How many moles of gold can be produced from 1.00 x 103 kg of ore? Assume 100% recovery

Answer 1

Proportion:

1000 kg – 100 %

x kg – 24.5 %

$x = \frac{1000 \times 24.5}{100} = 245 \; kg = 245 \times 10^3 \; g$

MM(Au) = 196.967 g/mol

$n(Au) = \frac{245 \times 10^3}{196.967} = 1.243 \times 10^3 \;mol = 1243 \;mol$

Answer: 1243 mol