Calculate the standard enthropy change to produce synthesis gas
CO(g) + H2(g) -> CH4(g) + H2O(g)
CO(g) + 3H2(g) → CH4(g) + H2O(g)
We know the ΔH0:
ΔH0=∑ΔHproducts0−∑ΔHreactants0=[ΔH0CH4(g)+ΔH0H2O(g)]–[ΔH0H2(g)+ΔH0CO(g)]=[−74.6+(−241.8)]−[3×0+(−110.5)]=−316.4+110.5=−205.9 kJΔH^0 = \sum ΔH^0_{products} -\sum ΔH^0_{reactants} \\ = [ΔH^0 CH_4 (g) + ΔH^0 H_2O (g)] – [ΔH^0 H_2 (g) + ΔH^0 CO(g)] \\ = [-74.6 +(-241.8)] -[3 \times 0 + (-110.5)] \\ = -316.4 +110.5 \\ = -205.9 \;kJΔH0=∑ΔHproducts0−∑ΔHreactants0=[ΔH0CH4(g)+ΔH0H2O(g)]–[ΔH0H2(g)+ΔH0CO(g)]=[−74.6+(−241.8)]−[3×0+(−110.5)]=−316.4+110.5=−205.9kJ
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments