If 0.1 mole of COC1₂, in a 1- liter vessel is 60% dissociated into CO and Cl, at a certain temperature, calculate the equilibrium constant, Kc.
Initially, 2 moles of CO are present.
At equilibrium, 1 mole of CO is present.
Hence, 2−1=1 mole of CO has reacted.
1 mole of CO will react with 1 mole of Cl 2 to form 1 mole of COCl2
3−1=2 moles of Cl2 remains at equilibrium.
The equilibrium constant
"K_c= \\frac{\\frac{1mol}{5L}}{\\frac{1mol}{5L}\u00d7\\frac{2mol}{5L}}"
"K_c= 2.5"
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