A sample of the black mineral hematite, an oxide of iron found in many iron ores. contains 34.97 g of iron and 15.03 g of oxygen . What is the empirical formula of hematite
Fe = 34.97g
O = 15.03g
Divide by molar mass
Fe = 34.97/56 = 0.624
O = 15.03/16 = 0.939
Divide by smaller number
Fe = 0.624/0.624 = 1
O = 0.939/0.624 = 1.5
Multiply by 2 to turn values to natural numbers
Fe = 2
O = 3
"\\therefore" The empirical formula of the compound is "Fe_2O_3"
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