number of H - ions in 5.44 g SrH2
The molar mass of SrH2 is 89.64 g/mol, and there are 2 moles of H- ions per 1 mole of SrH2. Therefore,
"Number\\ of\\ H^-=5.44\\ g(SrH_2)\\times\\frac{1\\ mol(SrH_2)}{89.64\\ g(SrH_2)}\\times\\frac{2\\ mol(H^-)}{1\\ mol(SrH_2)}\\times\\frac{6.022\\times10^{23}\\ ions(H^-)}{1\\ mol(H^-)}=7.31\\times10^{22}\\ ions"
Answer: "7.31\\times10^{22}"
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