How many joules are absorbed as the temperature of 15.0 grams of aluminum is heated from 20.0oC to 60.0oC?
"Q = mc\u0394T \\\\\n\u0394T = 60.0-20.0 = 40.0 \\\\\nm = 15.0 \\;g \\\\\nc_{Al} = 0.900 \\;J\/g \\cdot C \\\\\nQ = 15.0 \\times 0.900 \\times 40.0 = 540 \\;J"
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