Answer to Question #257685 in General Chemistry for Samatha

Question

A 36.0−g sample of an unknown metal at 99°C was placed in a constant-pressure calorimeter containing 60.0 g of water at 24.0°C. The final temperature of the system was found to be 28.4°C. Calculate the specific heat of the metal. (The heat capacity of the calorimeter is 13.4 J/°C.)

Answer 1

Heat lost by metal = -ms_metal∆T

=-36×S_metal×(28.4-99)

=(36×70.6)S_metal

Heat gain by water = 60×4.184×(28.4-24)

= 1104.58

1104.58= 2541.6S_metal

specific heat of the metal= 0.435