Answer to Question #253689 in General Chemistry for loc

Question

 

Using the method described in the Reactions of Copper experiment, calculate the mass of copper (II) hydroxide, Cu(OH)₂, that could be produced from 1.1005 g of pure copper metal.

Molar mass Cu = 63.55 g/mol

Molar mass Cu(OH)₂ = 97.561 g/mol

Answer 1

Cu (s) + 4 H3O (aq) + 2 NO3 (aq) --> [Cu(H2O)6]2 (aq) + 2 NO2 (g)

1.1005/63.55= 0.01732mol

Mole ratio= 1:1

0.01732× 97.561= 1.69g