Answer to Question #253448 in General Chemistry for Vaibhav

Question

2A + 3B --> 4C,

20.0 g of A reacted with excess of B. How many grams of C were obtained, if the molar mass of A is 26.0 g/mol and molar mass of C is 14.5 g/mol?

Answer 1

n(A) $= \frac{20.0}{26.0} = 0.7692 \;mol$

According to the reaction:

n(C) = 2n(A) $= 2 \times 0.7692 = 1.5384 \;mol$

m(C) $= 1.5384 \times 14.5 = 22.30 \;g$

Answer: 22.30 g