Solution.
"Q(cal.) = Q(reac.)"
"Q(cal.) = C(cal.) \u00d7 \\Delta T = 113.013 kJ"
"Q(reac\/mol) = \\frac{Q(reac.)}{n(CH6N2)}"
"n(CH6N2) = \\frac{m(CH6N2)}{M(CH6N2)}"
"n(CH6N2) = \\frac{4.00}{46.1} = 0.09 \\ mol"
"Q(reac\/mol) = \\frac{113.013 \\times 10^3}{0.09} = 1.30 \\times 10^6 \\ J\/mol"
Answer:
"Q(reac\/mol) = 1.30 \\times 10^6 \\ J\/mol"
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