Solution.
Q(cal.)=Q(reac.)Q(cal.) = Q(reac.)Q(cal.)=Q(reac.)
Q(cal.)=C(cal.)×ΔT=113.013kJQ(cal.) = C(cal.) × \Delta T = 113.013 kJQ(cal.)=C(cal.)×ΔT=113.013kJ
Q(reac/mol)=Q(reac.)n(CH6N2)Q(reac/mol) = \frac{Q(reac.)}{n(CH6N2)}Q(reac/mol)=n(CH6N2)Q(reac.)
n(CH6N2)=m(CH6N2)M(CH6N2)n(CH6N2) = \frac{m(CH6N2)}{M(CH6N2)}n(CH6N2)=M(CH6N2)m(CH6N2)
n(CH6N2)=4.0046.1=0.09 moln(CH6N2) = \frac{4.00}{46.1} = 0.09 \ moln(CH6N2)=46.14.00=0.09 mol
Q(reac/mol)=113.013×1030.09=1.30×106 J/molQ(reac/mol) = \frac{113.013 \times 10^3}{0.09} = 1.30 \times 10^6 \ J/molQ(reac/mol)=0.09113.013×103=1.30×106 J/mol
Answer:
Q(reac/mol)=1.30×106 J/molQ(reac/mol) = 1.30 \times 10^6 \ J/molQ(reac/mol)=1.30×106 J/mol
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