A reversible chemical reaction combines A and B to produce C and D according to
A+2B⇌
k
1
k
2
C+D.
A+2B⇌k1k2C+D.
At equilibrium, A, B and C are present in concentrations 1 M
M, 0.05 M
M, 500 mM
mM respectively.
If the rate constants are k
1
=2M
−2
s
−1
k1=2M−2s−1 and k
2
=1M
−1
s
−1
k2=1M−1s−1, what is the concentration of D
D
in M
M at equilibrium? Give the result to three significant figures.
[D]
[D] = M
500×0.05/2
= 12.5M
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