Answer to Question #253667 in General Chemistry for atenz

Question #253667

A reversible chemical reaction combines A and B to produce C and D according to 

A+2B⇌

k

1

k

2

C+D.

A+2B⇌k1k2C+D.

At equilibrium, A, B and C are present in concentrations 1 M

M, 0.05 M

M, 500 mM

mM respectively.

If the rate constants are k

1

=2M

−2

s

−1

k1=2M−2s−1 and k

2

=1M

−1

s

−1

k2=1M−1s−1, what is the concentration of D

D

in M

M at equilibrium? Give the result to three significant figures.

 

[D]

[D] =    M


1
Expert's answer
2021-10-20T02:53:21-0400

500×0.05/2

= 12.5M


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