Question

Consider Teflon, the polymer made from tetrafluoroethylene. (a) Draw a portion of the Teflon molecule, (b) Calculate the molar mass of a Teflon molecule that contains 5.0x10^4 CF_2 units (c) What are the mass percents of C and F in Teflon? [NOTE: underscores (_) refer to subscripts, while (^) indicates superscripts].
Match the best descrip

Answer 1

The monomer unit is tetrafluoroethylene which has the following basic unit.

The polymeric chain of Tetrafluoroethylene that is Teflon can be represented as follows:

The number of molecules of Tetrafluoroethylene contains in a polymer.

5.0x10⁴ molecules.

Moral mass of the polymer=Number of molecules of Tetrachloroethylene x Molar mass of Monomer

The molar mass of Monomer (Tetrafluoroethylene) = 100.02g/mol

Molar mass of the polymer

=5.0x10⁴ x100.02

=5.0x10⁶ g/mol

% Mass of C in the given polymer=

$\frac{weight \; of \; carbon \; in\; monomer}{total \; weight \; of\; the\; monomer} \times 100 \\ = \frac{2 \times12.01}{100.2} \times 100 \\$

=24.02%

% Mass of F in the given polymer = $\frac{weight \; of \; fluorine \; in\; monomer}{total \; weight \; of\; the\; monomer} \times 100 \\ = \frac{4 \times 19.0}{100.2} \times 100 \\$

=75.98%

Therefore, % Mass of C is 24.02% and F is 75.98%.

The monomer unit is tetrafluoroethylene which has the following basic unit.

The polymeric chain of Tetrafluoroethylene that is Teflon can be represented as follows:

The number of molecules of Tetrafluoroethylene contains in a polymer 5.0x10⁴ molecules.

Molar mass of the polymer= Number of molecules of Tetrachloroethylene x Molar mass of Monomer

The molar mass of Monomer (Tetrafluoroethylene) = 100.02 g/mol

Molar mass of the polymer

=5.0x10⁴ x100.02 g/mpl

=5.0x10⁶ g/mol

% Mass of C in the given polymer =

$\frac{weight \; of \; carbon \; in\; monomer}{total \;weight \; of \; the\; monomer} \times 100 \\ =\frac{2 \times 12.01}{100.2}\times 100 \\$

=24.02%

% Mass of F in the given polymer =$\frac{weight \; of \; fluorine \; in\; monomer}{total \; weight \; of\; the\; monomer} \times 100 \\ =\frac {4 \times 19.0}{100.02} \times 100 \\$

=75.98%

Therefore, % Mass of C is 24.02% and F is 75.98%.