Question

The reaction involved on the explosive combustion of acetylene is:

2 C₂ H₂(g) + 5 O₂(g)----- 4 CO₂(g) + 2 H₂ (g)

How many L of CO₂ gas(measured at STP) will be formed during the combustion of 50.0 L C₂H₂ gas(measured at STP)?

Answer 1

Molar mass of $C_2H_2= 26.04 g/mol$

Moles of $C_2H_2=\frac{50.0}{26.04}=1.92moles$

Moles ratio 2:4

Moles of $CO_2=\frac{4}{2}×1.92=3.84moles$

Mass of $CO_2= 44.01 ×3.84=169grams$

Hence $CO_2=169l$