A major ore of bismuth (III) sulfide, Bi_2S_3. By roasting in air, it is converted to the corresponding oxide; sulfur dioxide is a byproduct. What volume of SO_2 at 25 degrees Celsius and at 1 atm is formed when 0.5 tons (0.5 x 10^6 g) of ore containing 2.5% Bi_2S_3? (Hint: convert the mass of the Bi_2S_3 present in the ore to moles of Bi_2S_3 and then covert to moles of SO_2. Then use the ideal gas law [pV=nRT] to convert to the volume of SO_2) [NOTE: underscores (_) refer to subscripts, while (^) indicates superscripts].
1× 0.5 × 10^6
= 500g
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