Question #227184

If the reaction of the 20grams calcium carbonate with an expected theoretical yield of 18grams calcuim oxide produced a yield percentage of 80%, what is the actual yield of CaO?


1
Expert's answer
2021-08-19T02:45:01-0400

Actual yield =80×18100=14.4grams=\frac{80×18}{100}=14.4grams


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