Answer to Question #226906 in General Chemistry for Kem0

Question #226906
How would you prepare a solution containing 50mM NaCl (mwt = 58.5g/mol) and 10mM Na2HPO4 (358.057 g/mol) in a final volume of 250ml?
1
Expert's answer
2021-08-19T03:50:02-0400

Solution


1mM= 0.001M

"Molarity=\\frac{50mM\\times{0.001}}{1mM}=0.05M"

"Moles of NaCl=\\frac{250ml\\times{0.05mol}}{1000ml}= 0.0125 moles"

"Mass of NaCl = 58.44g\/mol\\times0.0125= 0.7 g""Molarity of Na_2HP0_4"

"\\frac{10mM\\times{0.001M}}{1mM}=0.01M"


"Moles= \\frac{250\\times{0.01}}{1000}= 0.025moles"


"Mass of Na_2HPO_4= 358.057\\times 0.025 moles = 8.95 g"


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