Question

How many grams of sulfosalicylic acid are needed to prepare 1 liter of 3% solution?

Answer 1

$\%$ $w\over v$ $=$ $g solute\over 100mL solution$ $\times 100 \%$

$g solute=1mL \times \%$

$=1\times 3\over 100$$=0.03 g$