Question

Calculate the number of moles of aluminium ion and tetraoxosulphate (vi)ion in 50cm^3 of 1molar aqueous solution of ammoniumtetraoxosulphate (vi)

Answer 1

$$(NH_4)_2SO_4 = 2NH_4^+ + SO_4^{2-}$$

$$n((NH_4)_2SO_4) = 0.05L*1M = 0.05 mol$$

$$n(NH_4^+) = 0.05mol*2 = 0.1mol$$

$$n(SO_4^{2-})=0.05mol$$