Answer to Question #222723 in General Chemistry for Hamo

Question

Calculate the amount of CaCo3 that would remain if 17g of CaCo3 are reacted with 0.25moles of dilute HCL

Answer 1

CaCO3(s) + 2HCl(aq) → CaCl2(aq) + CO2(g) + H2O(l)

Molar Mass of CaCO₃ =100.0869 g/mol

Mole ratio = 2:1

= 0.125 × 100.0896

= 12.5112

= 17-12.5112

= 4.49g