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Answer to Question #222723 in General Chemistry for Hamo
Question #222723
Calculate the amount of CaCo3 that would remain if 17g of CaCo3 are reacted with 0.25moles of dilute HCL
Expert's answer
CaCO3(s) + 2HCl(aq) → CaCl2(aq) + CO2(g) + H2O(l)
Molar Mass of CaCO3 =100.0869 g/mol
Mole ratio = 2:1
= 0.125 × 100.0896
= 12.5112
= 17-12.5112
= 4.49g
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