Question

If 25 g of C;H, reacts with excess oxygen, how many moles of water will be formed?

Answer 1

Solution

C:H we will work with methane as our hydrocarbon

Equation:

CH_4(g)+O_2(g)$\implies$ CO_2(g)+ 2H₂O_(g)

V(CH₄)$=\frac{m}{W}=\frac{25}{16}=1.5625 moles$

mole ratio CH₄ 1:H₂O 2

Moles of water $1.5625\times2= 3.125 moles$

Moles of water formed= 3.125 moles