Question #222162

21. Two of your friends, Rex and Cody, are having a disagreement. Rex argues that 0.020 M HCl is more acidic than 5.0 M CH3CH2COOH (pKa = 4.87) because nitric acid is a strong acid. Cody argues, however, that 5.0 M CH3CH2COOH (pKa = 4.87) is more acidic than 0.020 M HNO3 because it has a higher concentration. Who is correct? Prove your point by calculating both pHs.


1
Expert's answer
2021-08-02T12:26:18-0400

Solution

CH3CH2COOH(pKa=4.87)CH_3CH_2COOH(pKa=4.87)


pKa = 4.87


logka= -4.87


ka = 1.34×1051.34\times10^{-5}


[H+]=1.34×105×5.0[H^+]=\sqrt{1.34\times10^{-5}\times5.0}


=8.19×103=8.19\times10^{-3}


pH= -log(8.19×103)\times10^{-3}) = 2.09


pH of HCl=log(0.020)=1.70=log(0.020)=1.70


pH of HN03=log(0.020)=1.70=log(0.020)=1.70


Rex is correct propanoic acid is weaker compared to nitric acid because the lower the value of pH the stronger the acid.


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