Answer to Question #222165 in General Chemistry for Femi

Question

https://www.google.com/search?client=ms-opera-mini-android&channel=new&sxsrf=ALeKk01SY0sPniDmBpP6QCJBMB9FU-oEBw:1627742030823&q=272dm%5E3+of+a+gas+was+collected+over+water+at+20%5EoC+and+782+mmHg.Calculate+the+volume+of+gas+at+STD+(SVP+of+water+at+20%5EoC+%3D+12+mmHg)&spell=1&sa=X&ved=2ahUKEwifqaHMw43yAhUGnxQKHZNVBk8QBXoECA0QAQ

Answer 1

P₁=782-12=770mmHg,T₁=273+20=293K, V₁=272dm³, V₂=???=x, T₂=273k, P₂=760mmHg

By general gas law

P₁V₁/T₁=P₂V₂/T₂

=>V₂=P₁V₁T₂/P₂T₁

=770*272*273/(760*293)

=256.77dm³...