How many moles of copper(II) sulfate will react with 16.5 grams of
aluminum?
The balance chemical equation for the above is:
2Al+3CuSO4⟶Al2(SO4)3+3Cu2Al +3CuSO_4 \longrightarrow Al_2(SO_4)_3 +3Cu2Al+3CuSO4⟶Al2(SO4)3+3Cu
Moles of Aluminum =16.527=0.6moles= \dfrac{16.5}{27} =0.6 moles=2716.5=0.6moles
Now by the mole mole analysis :
The moles of ,the moles of copper (ii) sulfate =32×0.6=0.9moles= \dfrac{3}{2} \times 0.6=0.9 moles=23×0.6=0.9moles
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