How many moles of copper(II) sulfate will react with 16.5 grams of
aluminum?
The balance chemical equation for the above is:
"2Al +3CuSO_4 \\longrightarrow Al_2(SO_4)_3 +3Cu"
Moles of Aluminum "= \\dfrac{16.5}{27} =0.6 moles"
Now by the mole mole analysis :
The moles of ,the moles of copper (ii) sulfate "= \\dfrac{3}{2} \\times 0.6=0.9 moles"
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