Since the sample is a hydrocarbon, it contains Carbon and hydrogen in a specific ratio.
1GMW=22.4dm3
Molar mass of Hydrocarbon =56dm3
1GMW of CO2=12+2×24=44gm=12gmCarbon
= 4412 ×0.07=0.0191
% Carbon in the sample=85.71%
% Hydrogen in the sample =14.29%
Empirical formualr= 12.0185.71 =7.14
.1.007914.29 =14.29
=1:2
Formulae of Hydrocarbon=(CH2)n
=(12.011+2×1.0079)×n=56
=14.0268n=56
n=3.99=4
C4H8
Mass of Hydrocarbon =(12.011×4)+(1.0079×8)
=56.1072g
Comments