Answer to Question #205580 in General Chemistry for Ayat

Question

Write the electrochemical shorthand notation for a voltaic cell with the following reactions: (3 marks)

Pb2+(aq) + 2e- ⇌ Pb(s) E = -0.13V

Co2+(aq) + 2e- ⇌ Co(s) E = -0.28V

b) Write down the reaction that occurs at the anode. Is this oxidation or reduction?

c) Which substance would form the negative electrode?

d) What would be the potential difference measured by a voltmeter for this cell?

Answer 1

a) Electrochemical notation

Pb | Pb²⁺ (1M) || CO²⁺ (1M)| CO

b) Reaction that occurs at the anode

Co2+(aq) + 2e- ⇌ Co(s)

It is Oxidation

c) reaction that occurs at the negative electrode

Pb2+(aq) + 2e- ⇌ Pb(s)

d) potential differences is the sum of the volts within a reaction

= -0.13 + - 0.28

= -0.41V