Question

The chloride in the sample is to be determined gravimetrically by precipitating and weighing AgCl. What weight

in grams of sample should be taken so that the percentage of Cl is obtained by simply multiplying the weight of

the AgCl precipitate by 10?

Answer 1

$\omega=\frac{m(AgCl)\times0.247\times100}{m(sample)}$;

If $\omega=m(AgCl)\times10$, then $\frac{24.7}{m(sample)} = 10$, so m(sample) = 2.47 g

Answer: m(sample) = 2.47 g.