Question #195352

A 10.0 mL solution is 0.50 M silver nitrate. What minimum volume (in milliliters) of 0.10M sodium acetate is required to ensure precipitation of silver acetate is required to ensure precipitation of silver acetate given that ksp (AgCH3COO) = 4.0x10-3?


Expert's answer

AgNO3+CH3COONaCH3COOAg+NaNO3AgNO_3 + CH_3COONa \to CH_3COOAg+ NaNO_3


Ksp=[Ag+][CH3COO]4.0×103=[0.005][x]K_{sp} = [Ag^+][CH_3COO^-]\\ 4.0×10^{-3}= [0.005][x]

x=0.8Mx = 0.8M

minimum volume (in milliliters) is 8ml.


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