Question

What is the mole fraction of Carbon Dioxide?

A. 0.0556

B. 0.0670

C. 0.2567

D. 0.6676

E. 0.7572

Answer 1

Mole fraction of $CO_2$ is

$8360 torr\times 1atm\over760 torr$ $=11atm N_2$

$\frac {101.1 kPa × 1 atm} {101.32} 101.32 101.1kPa×1atm ​ = 0.998 atm Ar$

$\frac {760 mm Hg × 1 atm} {760 mm Hg} 760mmHg 760mmHg×1atm ​ = 1 atm CO2$

$Total Pressure = 11 atm + 5 atm + 0.998 atm +1 atm = 17.998 atm$

$mole fraction = \frac {5 atm} {17.998} 17.998 5atm ​$

$Mole fraction of Carbon Dioxide= 0.2767$ The correct answer is therefore $C$

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