1.00 mL of a 2.90x10-4 M solution of oleic acid (C18H34O2) is diluted with 9.00 mL of petroleum ether (C6H14), forming solution A. Then 2.00 mL of solution A is diluted with 8.00 mL of petroleum ether, forming solution B. What is the concentration of solution B?
We will use dilution formula two times
For solution A
M1V1=M2V2
2.90x10-4 *1=9M2
M2= 0.32x10-4
FOr solution B
0.32x10-4 *2=8*M2
M2= 0.08x10-4
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