What mass of CoCl3 is formed from the reaction of 3.478x10^23 atoms Co with 57.92L of Cl2 gas at STP?
The reaction between Co and Cl2to produce CoCl3
is given by,
2Co + 3Cl2→ 2CoCl3
2 mol 3 mol 2 mol
117.86 g 212.73 g 330.58 g
Now from the above balanced chemical reaction
Let Co be completely consumed in the reaction,
since 117.86 g of Co produces =330.58 g of CoCl3
So 1 g of Co produces ="\\frac{330.58}{117.86} g" Of CoCl3
Hence 34.00g of Co will produce :-
"=\\frac{34.00\u00d7330.58}{117.86} g" of CoCl3
="95.36g" of CoCl3
Hence, the amount of CoCl3 formed would be 95.36gram
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