Question

Use the following information: A container has 8360.0 torr of Nitrogen, 5.000 atm of Oxygen, 101.3 kPa of Argon, and 760.0 mm Hg of Carbon Dioxide.

What is the mole fraction of Oxygen?

A. 0.1673

B. 0.2670

C. 0.2778

D. 0.4675

E. 0.5782

Answer 1

8360 torr x 1 atm/760 torr = 11 atm N₂

5 atm O₂

101.1 kPa x 1 atm/101.32 = 0.998 atm Ar

760 mm Hg x 1 atm/760 mm Hg = 1 atm CO₂

Total Pressure = 11 atm + 5 atm + 0.998 atm +1 atm = 17.998 atm 

mole fraction O₂ = 5 atm/17.998 = 0.2778 (C)