Answer to Question #194312 in General Chemistry for elani ratchkovska

Question

A gas has a volume of 19.56 L at a temperature of 183 K. What will its volume be at a temperature of 327 K?

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A gas has is cooled from 106.43 oC to 43.15 oC. If its final volume is 4.79 L, what was its initial volume?

A gas is heated and its volume increases from 5.02 to 18.16 L. If the final temperature is 118 oC what was its initial temperature in Kelvin?

The volume of a gas increase from 3.43 to 8.80 L. If the initial temperature was 107 K, what is the final temperature?

If a gas has a volume of 22.30 L at 481 K, at what temperature will it have a volume of 7.83 L?

Answer 1

$\frac{V_1}{T_1}=\frac{V_2}{T_2}$

$\frac{19.56}{183}=\frac{V_2}{327}$

$V_2=34.95l$

$\frac{V_1}{T_1}=\frac{V_2}{T_2}$

$\frac{V_1}{379.43}=\frac{4.79}{316.15}$

$V_1=5.75l$

$\frac{5.02}{T_1}=\frac{18.16}{391}$

$T_1=108.08K$