Question #194309

A gas has a volume of 3.28 L at a temperature of 28.80 oC and pressure of 0.37 atm. What is its volume if the pressure changes to 1.67 atm and the temperature changes to 43.81 oC?


A gas has a volume of 14.20 L at a temperature of 372.18 K and pressure of 3.54 atm. What is its temperature if the pressure changes to 1.25 atm and the volume changes to 5.60 L?


A gas is compressed to a volume of 16.80 L at a pressure of 2.70 atm and a temperature of 290.23 K. If the initial pressure was 1.39 atm and the initial volume was 31.21 L, what was the initial temperature?


What was the initial pressure on a gas if its volume changes from 4.15 L to 11.23 L, its temperature changes from 13.70 oC to 45.00 oC and its final pressure is 0.70 atm?


What was the initial volume of a gas if its pressure changes from 3.49 atm to 1.73 atm, its temperature changes from 140.67 K to 203.05 K, and its final volume is 8.78 L?



1
Expert's answer
2021-05-18T06:51:02-0400

Answer :-

for all parts we use

P1V1T1=P2V2T2\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}


1)V=0.37×3.28×316.81308.18×1.67=0.74LV=\frac{0.37\times3.28\times316.81}{308.18\times 1.67}=0.74L

we changed temperature to kelvin by adding 273


2)T=1.25×5.6×372.1814.2×3.54=51.82KT=\frac{1.25\times5.6\times372.18}{14.2\times3.54}=51.82K


3) T=290.23×1.39×31.2116.80×2.70=277.57K\frac{290.23\times1.39\times 31.21}{16.80\times2.70}=277.57K


4)P=286.7×11.23×0.704.15×318=1.72atmP=\frac{286.7\times11.23\times0.70}{4.15\times 318}=1.72atm

we changed temperature to kelvin by adding 273


5)V=140.67×8.78×1.733.39×203.05=3.10LV=\frac{140.67\times8.78\times 1.73}{3.39\times 203.05 }=3.10L


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