'A' reacts with 'B' in a one-step reaction to give 'AB'. The rate constant for the reaction is 2.0 x 10-3 L mole-1 sec-1 and neither A or B are 0th order. If the concentration of A is increased from 0.50 mole/L to 1.0 mole/L, what effect would this have on the rate of the reaction? Explain your answer.
The rate is proportional to the concentration of a reactant. When you double the concentration the rate doubles. The rate is proportional to the square of the concentration of a reactant. When you double the concentration the rate goes up four times.
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