If 4 moles of NH₃ (ammonia) and 3 moles of O₂ (oxygen gas) react in the reaction below, determine the EXCESS reactant. 4NH₃ + 5O₂ --> 4NO + 6H₂O
Total moles of "NH_3" react "=4\\times 4=16"
Total moles of "O_2" reacts "= 5\\times 3=15"
So Here Excess reactant is"NH_3."
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