If 4 moles of NH₃ (ammonia) and 3 moles of O₂ (oxygen gas) react in the reaction below, determine the EXCESS reactant. 4NH₃ + 5O₂ --> 4NO + 6H₂O
Total moles of NH3NH_3NH3 react =4×4=16=4\times 4=16=4×4=16
Total moles of O2O_2O2 reacts =5×3=15= 5\times 3=15=5×3=15
So Here Excess reactant isNH3.NH_3.NH3.
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