A sample of Oxygen gas has a volume of 8.40 L at a pressure of 105 kPa. What will the new volume of the gas be at a pressure of 205 kPa?
P1V1=P2V2P_1V_1=P_2V_2P1V1=P2V2
105×8.40=205×V2105×8.40= 205×V_2105×8.40=205×V2
V2=4.30LV_2=4.30LV2=4.30L
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