Suppose that 2.50 g of NaCl is required for a certain reaction. If the NaCl is available as a 0.150 molar solution, how many mL of the solution must be used?
Number of moles =2.5g58.44=0.042.78moles\frac {2.5g} {58.44}=0.04 2.78moles58.442.5g=0.042.78moles
V=0.042780.15=0.285LV=\frac {0.04278}{0.15}=0.285LV=0.150.04278=0.285L
V=285mL
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