A cell using Zn/Zn+2 (aq, 1M) and H2 / H+1 (aq, 1M) generates a cell potential of + 0.67 V under standard conditions.
A. Write the half-cell reaction at the anode.
B. Write the half-cell reaction at the cathode.
C. Write the electrochemical cell notation.
D. Calculate the standard reduction potential at the anode.
(A): "Zn^0 (s) = Zn^{2+} (aq)+ 2e^-"
(C): "2H^+(aq) + 2e^- = H_2(g)"
"E_{cell} = E^0(2H^+\/H_2) - \u0415^0(Zn^0\/Zn^{2+}) = 0.763 V"
Comments
Leave a comment