For the reaction shown, calculate how many moles of NO2 form when each amount of reactant completely reacts.
2N2O5(g)->4NO2(g)+O2(g)
4.72×103molN2O5
Express your answer using three significant figures.
From the balanced equation
2mol of N2O5 gives 4moles of NO2
Therefore,
4x103moles of N2O5 will give 8x103mol of NO2
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