Phenol(C6H5OH) is commonly used to make a buffer with Sodium Phenolate (C6H5ONa) . Given that the Ka = 1.29*10^-10, and a buffer was created with 0.25g of Phenol and 0.50g Sodium Phenolate. Determine the pH after the addition of 2mL of 0.10M HCI.
Molar Mass of Phenol = 94.11
0.25/94.11 = 0.00266M
Molar Mass of sodium phenolate = 116.09
= 0.5/116.09
= 0.00431M
Molar Mass of HCl 36.458
36.458 × 0.1
= 3.6458 ×2
= 7.2916/36.458
= 0.2moles
0.2/0.75 = X/1L
= 0.15 of H+
PH =14+ -log(0.15)
= 14+0.82
= 14.82
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