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Find the pH of the acid before any NaOH is added show all work and the ICE TABLE
pH of the acid before any NaOH is added
The pH of the solution will thus be
pH=−log([H3O+])pH=−log([H_3O^+])pH=−log([H3O+])
pH=−log(2.3143×10−4)=3.64pH=−log(2.3143×10^{−4})=3.64pH=−log(2.3143×10−4)=3.64
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