Question

What mass of BaCl₂ is needed to dissolve in 1.2kg water to prepare 0.500m of BaCl₂ solution?

Answer 1

1 m Solution contains = 1 Mole of the solute in 1000 g of the solvent.

(Molecular Mass of BaCl2= 208.23 g

Therefore weight BaCl2 (anhydrous) to be added to 1.2 Kg of water to prepare 1m

$Solution = 1.2 × 208.23 =249.876 g$

So to prepare 0.500m BaCl2 the weight of BaCl2 to be added to 1.2 Kg of water $=\frac{249.876}{2}= 124.938 g$