Answer to Question #184617 in General Chemistry for Sachitha

Question

How many grams of H2O will be formed when 32.0 g H2 is allowed to react with 16.0 g O2 according to 2 H2 + O2 → 2 H2O

Answer 1

$H_2​+\frac{1}{2}​O_2→H_2​O$

 

1 mole of H2 combines with a half mole of O2

​ to form one mole of H2​O.

The molecular weights of H2, O2and H2O are 2 g/mol, 32 g/mol and 18 g/mole respectively.

2 g (1 mole) of H2 combines with 16 g (half mole) of O2 to form 18 g (one mole) of H2O.

We have 32.0g H2​ is mixed with 16.0g O2

​

Out of this, 2.0g H2 will combine with 16.0g O2

since oxygen mass is limited. 

18 g (one mole) of H2​O will be obtained.