A cell using Zn/Zn+4 (aq, 1M) and H2 / H+1 (aq, 1M) generates a cell potential of + 0.67 V under standard conditions.
A. Write the half-cell reaction at the anode.
B. Write the half-cell reaction at the cathode.
C. Write the electrochemical cell notation.
D. Calculate the standard reduction potential at the anode.
A. Zn - 2e = Zn2+
B. 2H+ + 2e = H2
C. Zn | Zn2+ || H+ | H2, Pt
D. Ecell = EH - EZn
EH (cathode) = 0V
EZn (anode) = EH - Ecell = 0 - 0.67V = -0.67V
Comments
Leave a comment