Calculate the mass of gaseous SO2 that will be produced along with 1233 g of copper from the roasting of copper(II) sulfide.
CuS(s) + O2(g) Cu(s) + SO2(g)
"CuS_{(s) }+ O_{2(g)} \\to Cu_{(s)} + SO_{2(g)}"
molar mass of copper = 65.5g
number of moles of copper = 1233/65.5 = 18.8 moles
1 mole of copper is produced by 1 mole of SO2
1 mole of CuS produces 1 mole of SO2
1 moles of CuS produces 64.06g of SO2
"\\therefore" 18.8 moles of CuS produces 1204.32g of SO2
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